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2.2v LED off 12v battery, what do I need?

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Teflon-Mike
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PostPosted: 03:00 - 08 Jan 2011    Post subject: 2.2v LED off 12v battery, what do I need? Reply with quote

Just bought an iluminated switch. Nievely I presumed it had a 12v bulb in it, like they always used to but getting it home, discovered it has a 2.2v 0.025a LED in it instead.
Need this to light up when I turn the switch 'on'.
So need to take feed off the switch out-put to the LED and thence to earth.
However, resistor networks are not my forte.
I THINK, from =IR, that it must equate to a resistance of 88 Ohms.
Now, I guess I need a resistor in series with it to drop the voltage.
But getting stuck on the maths. How big a resistor do I need?
And do I put it BEFORE the LED or after, or doesn't it matter?
Or is thre a better way of doing it, with a bridge circuit or something?
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stinkwheel
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PostPosted: 03:29 - 08 Jan 2011    Post subject: Reply with quote

Simple ohms law question. V=IR

Your LED draws 0.025A. Needs 2.2V and is supplied with 12V

12V-2.2V = 9.8V

V = IR
9.8 = 0.025R

R= 392Ω

So a 400R resistor should do the trick. On either leg will be fine but traditionally on the +ve leg.

EDIT: That's for a stable 12V circuit. On a bike it'll be closer to 14V most of the time so 11.8 = 0.025R
R=472Ω
So a 480R resistor.
____________________
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I did the 2010 Round Britain Rally on my 350 Bullet. 89 landmarks, 3 months, 9,500 miles.
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Codemonkey
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PostPosted: 10:23 - 08 Jan 2011    Post subject: Reply with quote

Adding to the post above, it will need to be rated at 0.3W or above since P=(I*I)*R
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Fortuna
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PostPosted: 17:43 - 08 Jan 2011    Post subject: Reply with quote

stinkwheel wrote:
Simple ohms law question. V=IR

Your LED draws 0.025A. Needs 2.2V and is supplied with 12V

12V-2.2V = 9.8V

V = IR
9.8 = 0.025R

R= 392Ω

So a 400R resistor should do the trick. On either leg will be fine but traditionally on the +ve leg.

EDIT: That's for a stable 12V circuit. On a bike it'll be closer to 14V most of the time so 11.8 = 0.025R
R=472Ω
So a 480R resistor.

Not to be pendantic (the formula is correct) but you should calculate on the running or charging voltage when working on automotive calculations.
EDIT: I should read your EDIT Smile
I've thumbed up anyway Thumbs Up
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Teflon-Mike
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PostPosted: 18:26 - 08 Jan 2011    Post subject: Reply with quote

OK, to get this straight, becouse I dissapeared up my own back-side in a frustrated rage if trying to remember where R=sum of 1/R's and whether I needed roughly 5x the resistance of the LED or 1/5th!

Bike +ve Supply-----SWITCH---------RESISTOR-------Switch LED--------- Bike Ground

That's the circuit... or at least the bit we're concerned with.

Switch LED = 2.2v, 0.025a (I am correct that's an 88Ohm resistance then?)

And at a notional 12v-ish I need a 470 Ohm resistor infront of it, to drop the volts to what the LED will handle.

Maplins: 330Ω to 910Ω Metal Film 0.6W Resistors..(for 24p!).. I take it I'm looking in the right kind of place?

Given comments over fluctuation in supply voltage, Lets say between 10v and 15v....
470/88 = 5.34:1 so (am I right in the maths here?) for 10-15v supply, 1.8 to 2.8v accross my switch LED?

And at nominal line volts of between 11.5 & 13.5, 2.15 to 2.5v? Does this sound about right?

I Put a single 1.2v Rechargeable AA battery accross the LED and it didn't light, two, it did. So, switch LED should 'work' still on lower end battery volts, and not 'blow' on higher end?

OK. ANOTHER bludy trip over to Coventry for a chuffing penny part should have this 'sorted'! Its for the indicators on Snowie's Pup BTW.

It now has LED's all round, and an electronic flasher to govern the flash-rate. And a fuse box with protection JUST for the Indicator flasher in it! And the LED Dash-tell-tale, curtecy of two 22p diodes, now works, and we dont have the wrong-side indicators working through it! But she decided she liked the idea of Hazard Warning Lamps..... so two more 94p diodes later, and we by-pass the indicator switch and get all four indicators blinking, and dont have the wrong-side indiators working through the hazard circuit.... but only works when the key is in the ignition.... two MORE 94p diodes, and the hazards are working off the parking light circuit, and the parking lights aren't flashing with the indicators! Just dont have the 'independent' tell-tale for the Hazards demanded by C&U, hence light up switch!... and now a resistor! And I'm fed up of hearing "It'll be a great bike, when its done" yeah... you come get solder balls burning through your jeans into your nuts, then!

thanks all.
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My Webby'Tef's-tQ, loads of stuff about my bikes, my Land-Rovers, and the stuff I do with them!
Current Bikes:'Honda VF1000F' ;'CB750F2N' ;'CB125TD ( 6 3 of em!)'; 'Montesa Cota 248'. Learner FAQ's:= 'U want to Ride a Motorbike! Where Do U start?'
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WD Forte
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Joined: 17 Jun 2010
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PostPosted: 20:26 - 08 Jan 2011    Post subject: Reply with quote

As said, the running voltage if bikes/cars is nearer 14V rather than the nominal 12V

I usually use 1K resistors on std leds and under run them a bit
for longevity
A 1k will run it at 14 millamps which is usualy good enough
If you run them at or near their max stated current they may get hot and fail sooner
I doubt you need to have stuff lit up like a christmas tree especially
at night when it may be distracting or annoying.
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Last edited by WD Forte on 20:27 - 08 Jan 2011; edited 1 time in total
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Ichy
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PostPosted: 20:27 - 08 Jan 2011    Post subject: Reply with quote

Mike you lost me by the fourth sentence, does it work?

I guess the trouble with converting flashers into hazards is that the current direction is controlled by the indicator switch, sending the current either left or right.

Might have been easier to fit a switch that bypassed the handlebar switch flashing both sides at the same time.

Actually you could have used a cheap ebay alarm, I remember the last one i fitted had a silent alarm option, basically flashed all the indicators.
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Teflon-Mike
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PostPosted: 21:12 - 08 Jan 2011    Post subject: Reply with quote

Marki wrote:
Mike you lost me by the fourth sentence, does it work?

I guess the trouble with converting flashers into hazards is that the current direction is controlled by the indicator switch, sending the current either left or right.

Might have been easier to fit a switch that bypassed the handlebar switch flashing both sides at the same time.

Actually you could have used a cheap ebay alarm, I remember the last one i fitted had a silent alarm option, basically flashed all the indicators.


I was lost before the first sentence Marki!

PROBLEM is basically that I have an LED rated at 2.2v, and a motorcycle electrical system, rated at 12v to power it, and I dont want it to go 'pop' as soon as I switch it on!

Hazards; yes, basically I have tapped into the 'feed' for the Indicators, by-passed the direction switch, and fed it out to all four flashers.
BUT, had to use a pair of 6a diodes after the by-pass switch, before they T into the Left & right Indicator circuits, so that when the direction switch feeds them, doesn't cross flow back to the 'off' indicator.
However, indicators only work with the ignition 'on', so hazards wouldn't work if you hadn't got the key in the ignition.
So, took a feed from the park-light circuit to feed the flasher. So, tuen the key to 'park', you get side-light and tail, but now also power to the flasher unit, so the indicators and hazards will also work. BUT that meant I needed a pair of diodes there, so that the hazards and indicators could still run off the original ignition switched feed, without the side-lights on....

Clear as mud?

Basically four 94p diodes and a £2.30 switch, and when I get it, a 24p resistor, and she has, for under a tenner, a fully functioning Hazard circuit!

Only, doing 15 mile round trips to get each chuffing penny part, its costing me about ten times that in ruddy petrol!

Alarm? THAT is the next problem!
Remember this is a 1986 Honda CB125 Super-Dream. There's no fairings or anything to hide the siren or speaker, let alone the ruddy alarm unit! Space is at a premium. I'm struggling to squeeze in the six way blade-fuse box, and the smaller electronic flashicator, where the old bulky glass fuse holder and round flashicator used to live!

And we still have her heated grips to add and the power supply for her GPS! That one is actually quite important.

She took my bike to Leicester the other week. Coming back she got lost on the Nuneaton ring-road. Ended up half way to Coventry before she realised that the Number 48 bus she was following was coming out of town, not going into it!
____________________
My Webby'Tef's-tQ, loads of stuff about my bikes, my Land-Rovers, and the stuff I do with them!
Current Bikes:'Honda VF1000F' ;'CB750F2N' ;'CB125TD ( 6 3 of em!)'; 'Montesa Cota 248'. Learner FAQ's:= 'U want to Ride a Motorbike! Where Do U start?'
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Codemonkey
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PostPosted: 23:25 - 08 Jan 2011    Post subject: Reply with quote

Teflon-Mike wrote:
Maplins: 330Ω to 910Ω Metal Film 0.6W Resistors..(for 24p!).. I take it I'm looking in the right kind of place?


They should do!

Teflon-Mike wrote:

Given comments over fluctuation in supply voltage, Lets say between 10v and 15v....
470/88 = 5.34:1 so (am I right in the maths here?) for 10-15v supply, 1.8 to 2.8v accross my switch LED?

And at nominal line volts of between 11.5 & 13.5, 2.15 to 2.5v? Does this sound about right?


Not sure what you're doing there...

You have an LED which needs 2.2V at 25mA across it, and a 15V supply.

You need to drop 15V - 2.2V = 12.8V.

You need to drop a max of 12.8V at 25mA, so using ohms law, (V = I * R), rearranging to give R = V / I

so, R = V / I = 12.8V / 0.025A = 512 ohms (nearest standard value higher = 560 ohms so we'll use that).

Maximum power dissipation will be when dropping the max voltage, so P = I squared * R, therefore P = (0.025A * 0.025A) * 560 ohms = 0.35W

LED's will still have about 2.2V across them even when run at slightly higher or lower currents, so just assume its always dropping 2.2V. You need to see the datasheet for the LED in question to see the graph for forward voltage vs current to get the exact figures.

Calculating the current through the LED at 10V supply gives:

10V - 2.2V = 7.8V

I = V/R = 7.8V / 560ohms = 13.9mA which should still be enough to light it.

Hope that helps!
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Fortuna
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PostPosted: 20:55 - 14 Jan 2011    Post subject: Reply with quote

And ½ Watt Smile
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stinkwheel
Bovine Proctologist



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PostPosted: 21:57 - 14 Jan 2011    Post subject: Reply with quote

I'll just add.

For simplicity and to avoid going totally mental. When fitting LEDs to your 12v bikes system. It is far easier to work out which resistor your particular LED choice requires and solder one to each LED. You can then consider each LED to be effectively "plug and play" into the bikes electrical system.

It's not elegant and could be considered wasteful of componants but given the absurd cheapness of resistors, it makes life a whole lot easier. You just spend a half-hour session soldering resistors onto your bag of LEDs and they're ready to rock.

I get my electronic componants from CPC. A pack of 100x 0.25W 470R carbon film resistors is 54p (so £0.0054 each).

The trouble is you need to spend £40 to get free postage. That said they stock a truly awesome range of stuff, power tools, electronics, computer componants and so-on so I usually tack any consumables onto an order for something else.

cpc.farnell.com
____________________
“Rule one: Always stick around for one more drink. That's when things happen. That's when you find out everything you want to know.
I did the 2010 Round Britain Rally on my 350 Bullet. 89 landmarks, 3 months, 9,500 miles.
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Teflon-Mike
tl;dr



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PostPosted: 19:12 - 15 Jan 2011    Post subject: Reply with quote

Fortuna wrote:
And ½ Watt Smile

You mean like all my kids can muster instead of 'Pardon'...... "Y'Wha?"
You know, Jame's Watt might have been the bloke responsible for defining the principles of 'Power', but it's his brother 'Arthur', who seems so more frequently mentioned.....

Cheers stink.. TBH I've never really messed with LED's, unless they have come pre-wired as part of something else. This ones an anomoly, having bought an illuminated switch with uses one, where all I have ever bought before have had a conventional 12v tungsten bulb in them.
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My Webby'Tef's-tQ, loads of stuff about my bikes, my Land-Rovers, and the stuff I do with them!
Current Bikes:'Honda VF1000F' ;'CB750F2N' ;'CB125TD ( 6 3 of em!)'; 'Montesa Cota 248'. Learner FAQ's:= 'U want to Ride a Motorbike! Where Do U start?'
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