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Rotational Inertia

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Mikey3
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PostPosted: 17:31 - 13 Jan 2012    Post subject: Rotational Inertia Reply with quote

Is there a simple way to explain the mentioned subject, without all the complicated formulas and calculations?
Trying to understand it in relation to suspension.
Thanks Very Happy
Mike
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stinkwheel
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PostPosted: 17:44 - 13 Jan 2012    Post subject: Reply with quote

It's the resistance to a change in direction by applying an unbalanced force to a mass currently subjected to a balanced force.

Or even more simply. The tendancy of moving objects to keep moving in the direction they are already going and of stationary objects to remain stationary.
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Mikey3
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PostPosted: 17:52 - 13 Jan 2012    Post subject: Reply with quote

thank you Smile
I understand that now, but how does that link into suspension and types of suspension increasing and reducing rotational inertia?
Mike
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Teflon-Mike
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PostPosted: 18:13 - 13 Jan 2012    Post subject: Reply with quote

OK, if you lean against a mini, you can probably push it up the road with the hand brake on, becouse it ent very heavy, yeah? Try that with a Midland Red bus... well you ent going to shift it are you, even if the hand brake was off and you had a few mates to help.

Heavier something is, more effort it takes to get it moving, or make it change direction.

Moments of inertia are about making things move AND change direction.

Instead of 'forces' we are looking at 'torques' a force multiplied by an amount of leverage.

So, heavy flywheel, takes more energy to spin it up, becouse it is heavy, than a lighter one. BUT most of the resistance is coming from the mass at the rim of the wheel, which has to be accelerated further and faster becouse its further away from the axle.

So, if you take metal away from the midle, but keep the weight at the rim, you get nearly as much flywheel effect...

The moment of inertia being MASS x its distance from the axle.... so a small flywheel with a LOT of mass at its rim can have the same moment of inertia as a big flywheel with most of its mass packed around the axle.....

On to suspension.....

Suspension moves up and down, BUT, on a swing arm system, its not moving in a straight line, but an arc... if you let the swing arm rotate all the way around you could transcribe a full circle with it...

So same deal... moment of inertia is how much 'flywheel effect' the suspension links all have, and its quite important, becouse you tend to have a long swing arm, fixed at the pivot on the frame, supporting the pritty big mass of the wheel at it's far end.

Wheel is heavy and the swing arm long, so it will have a LOT of flywheel effect and NOT want to accelerate very much when you give it a shove.... like a bump does....

Worse, having got it moving, very soon after you are going to want to slow it down and shove it back again.... yeah?

So the lighter the assembly, and the less 'flywheel effect' or moment of inertia it has, the more easily it will go up or down... hence the more 'responsive' the suspension will be...

Responsive suspension is useful, because if you have the wheel still wanting to carry on going 'up' after hitting a big bump, the wheel can 'ramp' over the top of the bump and loose contact with the surface, and if you have a succession of bumps, rather than following the surface and keeping the tyre in close contact with the road, you can sort of ride the crests, skipping from one to the next.

SO; we have 'unsprung mass' which is the total amount of weight thats hung on the suspension a bump has to shift, and we want that as low as possible, BUT we also have the moment of inertia, and if we have a heavy braced swing arm, where a lot of the mass is packed around the pivot, we can tolerate that more, as it adds less to the moment of inertia, than if its hanging on the end of teh swing arm, where it has a lot further to move and has much more effect on the suspension responsiveness.

Make sense?
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G
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PostPosted: 18:18 - 13 Jan 2012    Post subject: Reply with quote

mredhead wrote:
thank you Smile
I understand that now, but how does that link into suspension and types of suspension increasing and reducing rotational inertia?
Mike

I think TM is saying is that "It doesn't"?
Can't see how suspension it's self can directly change this.

On a car you might say go for bigger tyres on smaller wheels that had more flex, meaning you didn't need the suspension needed to so much (as they do with F1).

But can't see how different types of suspension would change this concept.

Incidentally, on this... an interesting example of people playing with it is 'rim brakes' as seen on the Buell.

It has a single brake disc which sticks in from the rim rather than out from the hub.
This will have a lot higher rotational inertia it's self.
However, it's replacing two discs on a normal wheel and also means that spokes can be a fair bit lighter, as they're no longer transferring braking forces from the hub to the outer wheel.
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Mikey3
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PostPosted: 18:39 - 13 Jan 2012    Post subject: Reply with quote

I won't quote Laughing but yes, Thank you teflon, a long explained explanation is what i needed, Much much clearer now

and G - Yeah i understand it doesn't, just the wording of the Haynes book confused the s**t outta me! And generally assumes you know stuff like this, providing no explanation even in the 'technical terms explained' section. Which doesn't help.

so a clear up, its easy to shove a penny miles along the floor (suface providing) but a large tyre or something with much larger diameter, is a lot harder to get moving, and so, stop moving, due to it's rotational inertia or 'moment of inertia'?

Thanks guys Very Happy
Mike
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pepperami
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PostPosted: 18:40 - 13 Jan 2012    Post subject: Reply with quote

If you want to experiance rotational inertia to help you to understand it a tiny bit better do the following.

Get a bycycle wheel and spindle, put the spindle in the wheel and hold both ends of the spindle, then get a friend to spin the wheel, once it is spinning try moving the axis of the spindle.

It will give a little idea about what is going on with your wheel when you try to change direction Thumbs Up
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Mikey3
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PostPosted: 18:44 - 13 Jan 2012    Post subject: Reply with quote

G wrote:

Incidentally, on this... an interesting example of people playing with it is 'rim brakes' as seen on the Buell.

It has a single brake disc which sticks in from the rim rather than out from the hub.
This will have a lot higher rotational inertia it's self.
However, it's replacing two discs on a normal wheel and also means that spokes can be a fair bit lighter, as they're no longer transferring braking forces from the hub to the outer wheel.


So in this case the benefits of weight saving, as well as the disc being on the rim increases the 'leverage on a pivot' and so more braking force, outweighs the increased rotational inertia gained from it? positives outweigh the negatives?
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Mikey3
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PostPosted: 18:46 - 13 Jan 2012    Post subject: Reply with quote

pepperami wrote:
If you want to experiance rotational inertia to help you to understand it a tiny bit better do the following.

Get a bycycle wheel and spindle, put the spindle in the wheel and hold both ends of the spindle, then get a friend to spin the wheel, once it is spinning try moving the axis of the spindle.

It will give a little idea about what is going on with your wheel when you try to change direction Thumbs Up


That helps too, I've felt this so I can put 2 and 2 together Smile
thank you
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Mikey3
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PostPosted: 18:50 - 13 Jan 2012    Post subject: Reply with quote

Babba wrote:

WHY?

Are you trying to design your own chassis?


I'm trying to teach myself and amongst motorcycle suspension rotational inertia came up. I understand inertia, but i didn't understand rotational inertia, perhaps the context and the wording that was used, as it's got me a couple of times before - when you don't understand it fully some of the wording and terminology used is like WTF?!
So in order for me to understand it fully, i looked online, found nothing but calculations after a couple of searches, so i thought i'd ask on here, just to help me to understand and have that 'Ahhhh!' moment you speak of Razz
Mike
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G
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PostPosted: 18:57 - 13 Jan 2012    Post subject: Reply with quote

mredhead wrote:

So in this case the benefits of weight saving, as well as the disc being on the rim increases the 'leverage on a pivot' and so more braking force, outweighs the increased rotational inertia gained from it? positives outweigh the negatives?

It should lead to overall decreased rotational inertia is the idea.
More for that disc, but only one disc and less on the wheel.

The leverage on pivot would be the same I expect - stop at .5g and you've still got the bike pushing on to the front wheel spindle at .5g.

pepperami:
I think that's really more an explanation of gyro forces, which is a part of rotation inertia but I wouldn't directly see the term describing just them.
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Frost
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PostPosted: 19:06 - 13 Jan 2012    Post subject: Reply with quote

Surely rotational inertia does play a small part for bike suspension as a swing arm is a pivot. So the heavier the rear wheel, tire and swing arm are the more rotational inertia there is to overcome to get the wheel moving or stop the wheel moving with the spring.
It's likely to be quite a large effect, but fairly consistent between all bikes and will have been taken into consideration at the design phase.

As said above the rotational inertia is responsible for the gyroscopic effects of the wheels which must be taken into account when designing suspension systems, setting steering head angles etc But this is all done in computer simulation before a bike is built and should never need to be worried about by a normal user. Even someone building their own bike would get by perfectly well by copying an existing bike or by simple trial and error.
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Teflon-Mike
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PostPosted: 19:06 - 13 Jan 2012    Post subject: Reply with quote

mredhead wrote:
So in this case the benefits of weight saving, as well as the disc being on the rim increases the 'leverage on a pivot' and so more braking force, outweighs the increased rotational inertia gained from it? positives outweigh the negatives?


Rim discs are something of a curiocity; the effect of mounting a rim disc on a motorbike wheel instead of a hub disc has insignificant effect in relation to the flywheel & gyroscope effects of the wheel but they 'might' offer a gross weight saving on the assembly.

Braking force at the wheel's contact patch is the torque imposed on the wheel by the brake, which is itself the torque imposed on the wheel from the brake pad biting into the disc.

So we have a see-saw. Pad force times rotor radius gives you one end; wheel radius x braking force, the other.

Makes no odds to braking force which way round the caliper grips the disc, only how hard it grips and how big the disc is.

BUT you cant make the disc bigger than the wheel, for obviouse reasons; biggest you can make it is the rim diameter, hence a rim disc is about as big as you can practically get.

Mounting a disc that big though obviousely means it has to be pretty big, which would mean heavy, but cutting the middle out and mounting it on the rim, so they share a common centre obviousely saves a fair bit of mass.

This is probably the main area a rim disc offers any real advantage., though, having a bigger disc means that for the same braking force you need less 'pad' force, but you get a higher surface speed...

Having a lower pad force means you can probably use a lighter caliper, as it wont need so much re-inforcement to contain the pressure being put on the pads.
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Mikey3
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PostPosted: 19:09 - 13 Jan 2012    Post subject: Reply with quote

G wrote:
mredhead wrote:

So in this case the benefits of weight saving, as well as the disc being on the rim increases the 'leverage on a pivot' and so more braking force, outweighs the increased rotational inertia gained from it? positives outweigh the negatives?

It should lead to overall decreased rotational inertia is the idea.
More for that disc, but only one disc and less on the wheel.

The leverage on pivot would be the same I expect - stop at .5g and you've still got the bike pushing on to the front wheel spindle at .5g.
.


YEP i had a 'ahhhh' moment, it decreases it because its in from the rim, rather than out from the hub, i know thats what you said, but it just clicked Razz
So say a large diameter disc, like those used on large capacity sports bikes, and racing, would have high rotational inertia but in THIS case the stopping force and lightweight properties outweigh the increased inertia?
Mike
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Frost
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PostPosted: 19:10 - 13 Jan 2012    Post subject: Reply with quote

A rim disc requires less sheer strength in the wheel spokes allowing them to be thinner and lighter.
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Pete.
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PostPosted: 19:19 - 13 Jan 2012    Post subject: Reply with quote

Frost wrote:
Surely rotational inertia does play a small part for bike suspension as a swing arm is a pivot.


Yes, but there is a thing called the 'small angle rule', where it isn't actually a hard and fast rule but for many applications if the angle is less than x degrees it can be regarded as negligible.

A swing-arm doesn't swing through many degrees - the inertia in a rear wheel and arm is so close to linear, you might as well regard it that way, because to need to do otherwise presumes you have such knowledge that you need not be asking the question in the first place.
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Mikey3
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PostPosted: 21:46 - 13 Jan 2012    Post subject: Reply with quote

i understand the question......
thats it Razz
are you part of that racing world then?
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Frost
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PostPosted: 23:02 - 13 Jan 2012    Post subject: Reply with quote

Babba wrote:
Here's one to ponder & keep you awake the rest of the night.

(A) A motorcycle rear wheel hits a bump at 50mph.

(B) It hits the same bump at 100mph.

Qu' 1. Are A & B equal in the work that the rear shock has to do?


Will do or has to do?
Will do less work when hit at the faster speed due to the reduced contact time, but will do the work faster. The tire will absorb less of the bump due to it's rotational inertia making it firmer.
Has to do both would be the same assuming consistency in terms of tire rigidity, but as said the tire would do less of the work at the higher speed giving the shock more work to do and a shorter time period in which to do it. Assuming of course that it is required for the tire to have the same amount of contact with the road surface.
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Mikey3
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PostPosted: 23:24 - 13 Jan 2012    Post subject: Reply with quote

idiot question?

all makes sense to me, except regarding the tyre rigidity at high speed, wouldnt that be more to do with centrefugal force instead of rotational inertia?
the tyre being pushed outwards by the centrefugal from high speed and therefore holding its shape more effectively by 'wanting' to continue in a straight line?
Its more a query than a correction Razz
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Mikey3
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PostPosted: 00:25 - 14 Jan 2012    Post subject: Reply with quote

going back to the original question, it seems to make relative sense.
so the closer the mass is to the centre of a pivot, the easier it is for a given torque to rotate the mass round the pivot compared to the same torque but with weight at a greater distance from the pivot?
The further out the mass from the pivot - the higher its rotational inertia?
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