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tatters |
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 tatters Exxon Valdez

Joined: 04 Jan 2004 Karma :   
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 Posted: 22:36 - 15 Feb 2023 Post subject: Heat loss Calculation |
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I am having a issue working out the heat lost of a building assembly does anyone know of a way to calculate the following? does not seem to be much info on-line to work out for a entire year.
A 258.55m2 area with RSI of 1.40 has a heat loss of 69356.74MJ over a year.
What would the same areas heat loss be if the RSI is 2.84? ____________________ Past:NRG50,AF1125(x2),NSR125RR,ZZR250,CX500,VFR400,KR1S,ZZR600(x2),CB400N,YZF1000(x2),KH125,Z200,FX400R,CBR954RR(x2)GPZ500S,GT550,VFR750F(x2),RD350N,XR650R,CBR600F,CB250,KDX250,YZF750R,CRM250,400EXC,KLR650,TTR600RE,DR350S,R100GSPD,RGV250,VMAX1200,DL650,KZ750 Present:G650XC,C12,CRF450X,1190ADV |
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Easy-X |
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 Easy-X Super Spammer

Joined: 08 Mar 2019 Karma :   
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stinkwheel |
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 stinkwheel Bovine Proctologist

Joined: 12 Jul 2004 Karma :    
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Easy-X |
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 Easy-X Super Spammer

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tatters |
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 tatters Exxon Valdez

Joined: 04 Jan 2004 Karma :   
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 Posted: 20:06 - 16 Feb 2023 Post subject: |
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Easy-X wrote: | Surface area in metres squared * (temperature differential / RSI) = energy loss in Watts
69356.74MJ per year = 2197.83W (1MJ per year = 0.031688764615413W)
258.55 * ( t / 1.40) = 2197.83
so your temperature differential = 12 degrees Celsius? Sounds about right...
258.55 * ( 12 / 2.84 ) = 1092.46W
1092.46W = 34474.68MJ per year |
Perfect thanks ____________________ Past:NRG50,AF1125(x2),NSR125RR,ZZR250,CX500,VFR400,KR1S,ZZR600(x2),CB400N,YZF1000(x2),KH125,Z200,FX400R,CBR954RR(x2)GPZ500S,GT550,VFR750F(x2),RD350N,XR650R,CBR600F,CB250,KDX250,YZF750R,CRM250,400EXC,KLR650,TTR600RE,DR350S,R100GSPD,RGV250,VMAX1200,DL650,KZ750 Present:G650XC,C12,CRF450X,1190ADV |
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